65 lines
1.5 KiB
Markdown
65 lines
1.5 KiB
Markdown
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# Word Count
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Welcome to Word Count on Exercism's Python Track.
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If you need help running the tests or submitting your code, check out `HELP.md`.
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## Instructions
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Given a phrase, count the occurrences of each _word_ in that phrase.
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For the purposes of this exercise you can expect that a _word_ will always be one of:
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1. A _number_ composed of one or more ASCII digits (ie "0" or "1234") OR
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2. A _simple word_ composed of one or more ASCII letters (ie "a" or "they") OR
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3. A _contraction_ of two _simple words_ joined by a single apostrophe (ie "it's" or "they're")
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When counting words you can assume the following rules:
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1. The count is _case insensitive_ (ie "You", "you", and "YOU" are 3 uses of the same word)
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2. The count is _unordered_; the tests will ignore how words and counts are ordered
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3. Other than the apostrophe in a _contraction_ all forms of _punctuation_ are ignored
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4. The words can be separated by _any_ form of whitespace (ie "\t", "\n", " ")
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For example, for the phrase `"That's the password: 'PASSWORD 123'!", cried the Special Agent.\nSo I fled.` the count would be:
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```text
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that's: 1
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the: 2
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password: 2
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123: 1
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cried: 1
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special: 1
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agent: 1
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so: 1
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i: 1
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fled: 1
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```
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## Source
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### Contributed to by
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- @behrtam
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- @c4llmeco4ch
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- @cmccandless
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- @Dog
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- @gabriel376
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- @Grociu
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- @guygastineau
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- @ikhadykin
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- @jackattack24
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- @kytrinyx
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- @lowks
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- @N-Parsons
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- @pheanex
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- @rivergillis
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- @samdec11
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- @sjakobi
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- @tqa236
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- @wobh
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- @yawpitch
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- @ZacharyRSmith
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### Based on
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This is a classic toy problem, but we were reminded of it by seeing it in the Go Tour.
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