add a new exercise
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{
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"blurb": "Given a phrase, count the occurrences of each word in that phrase.",
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"authors": [],
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"contributors": [
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"behrtam",
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"c4llmeco4ch",
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"cmccandless",
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"Dog",
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"gabriel376",
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"Grociu",
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"guygastineau",
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"ikhadykin",
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"jackattack24",
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"kytrinyx",
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"lowks",
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"N-Parsons",
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"pheanex",
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"rivergillis",
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"samdec11",
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"sjakobi",
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"tqa236",
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"wobh",
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"yawpitch",
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"ZacharyRSmith"
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],
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"files": {
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"solution": [
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"word_count.py"
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],
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"test": [
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"word_count_test.py"
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],
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"example": [
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".meta/example.py"
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]
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},
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"source": "This is a classic toy problem, but we were reminded of it by seeing it in the Go Tour."
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}
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{"track":"python","exercise":"word-count","id":"bdd6135b0dbb4fec9695a92a43da8dce","url":"https://exercism.org/tracks/python/exercises/word-count","handle":"Nebucatnetzer","is_requester":true,"auto_approve":false}
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# Help
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## Running the tests
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To run the included *tests*, run the test file using the `pytest` module, replacing `{exercise_name}`:
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```bash
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$ python3 -m pytest {exercise_name}_test.py
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```
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Many IDE's and code editors have built-in support for using Pytest to run tests; check them out [here](https://github.com/exercism/python/blob/main/docs/TOOLS.md#editors-and-ides).
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For more information about running tests using `pytest`, checkout our [Python testing guide](https://github.com/exercism/python/blob/main/docs/TESTS.md#pytest).
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### Common pytest options
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- `-v` : enable verbose output.
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- `-x` : stop running tests on first failure.
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- `--ff` : run failures from previous test before running other test cases.
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For other options, see `python3 -m pytest -h`.
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## Submitting your solution
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You can submit your solution using the `exercism submit word_count.py` command.
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This command will upload your solution to the Exercism website and print the solution page's URL.
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It's possible to submit an incomplete solution which allows you to:
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- See how others have completed the exercise
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- Request help from a mentor
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## Need to get help?
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If you'd like help solving the exercise, check the following pages:
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- The [Python track's documentation](https://exercism.org/docs/tracks/python)
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- [Exercism's support channel on gitter](https://gitter.im/exercism/support)
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- The [Frequently Asked Questions](https://exercism.org/docs/using/faqs)
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Should those resources not suffice, you could submit your (incomplete) solution to request mentoring.
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Below are some resources for getting help if you run into trouble:
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- [The PSF](https://www.python.org) hosts Python downloads, documentation, and community resources.
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- [Python Community on Discord](https://pythondiscord.com/) is a very helpful and active community.
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- [#python on Libera.chat](https://www.python.org/community/irc/) this is where the cored developers for the language hang out and get work done.
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- [Exercism on Gitter](https://gitter.im/exercism/home) join the Python room for Python-related questions or problems.
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- [/r/learnpython/](https://www.reddit.com/r/learnpython/) is a subreddit designed for Python learners.
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- [Python Community Forums](https://discuss.python.org/)
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- [Pythontutor](http://pythontutor.com/) for stepping through small code snippets visually.
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Additionally, [StackOverflow](http://stackoverflow.com/questions/tagged/python) is a good spot to search for your problem/question to see if it has been answered already.
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If not - you can always [ask](https://stackoverflow.com/help/how-to-ask) or [answer](https://stackoverflow.com/help/how-to-answer) someone else's question.
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# Word Count
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Welcome to Word Count on Exercism's Python Track.
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If you need help running the tests or submitting your code, check out `HELP.md`.
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## Instructions
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Given a phrase, count the occurrences of each _word_ in that phrase.
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For the purposes of this exercise you can expect that a _word_ will always be one of:
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1. A _number_ composed of one or more ASCII digits (ie "0" or "1234") OR
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2. A _simple word_ composed of one or more ASCII letters (ie "a" or "they") OR
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3. A _contraction_ of two _simple words_ joined by a single apostrophe (ie "it's" or "they're")
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When counting words you can assume the following rules:
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1. The count is _case insensitive_ (ie "You", "you", and "YOU" are 3 uses of the same word)
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2. The count is _unordered_; the tests will ignore how words and counts are ordered
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3. Other than the apostrophe in a _contraction_ all forms of _punctuation_ are ignored
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4. The words can be separated by _any_ form of whitespace (ie "\t", "\n", " ")
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For example, for the phrase `"That's the password: 'PASSWORD 123'!", cried the Special Agent.\nSo I fled.` the count would be:
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```text
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that's: 1
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the: 2
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password: 2
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123: 1
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cried: 1
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special: 1
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agent: 1
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so: 1
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i: 1
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fled: 1
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```
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## Source
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### Contributed to by
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- @behrtam
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- @c4llmeco4ch
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- @cmccandless
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- @Dog
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- @gabriel376
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- @Grociu
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- @guygastineau
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- @ikhadykin
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- @jackattack24
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- @kytrinyx
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- @lowks
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- @N-Parsons
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- @pheanex
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- @rivergillis
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- @samdec11
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- @sjakobi
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- @tqa236
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- @wobh
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- @yawpitch
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- @ZacharyRSmith
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### Based on
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This is a classic toy problem, but we were reminded of it by seeing it in the Go Tour.
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def count_words(sentence):
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pass
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import unittest
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from word_count import (
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count_words,
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)
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# Tests adapted from `problem-specifications//canonical-data.json`
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class WordCountTest(unittest.TestCase):
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def test_count_one_word(self):
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self.assertEqual(count_words("word"), {"word": 1})
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def test_count_one_of_each_word(self):
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self.assertEqual(count_words("one of each"), {"one": 1, "of": 1, "each": 1})
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def test_multiple_occurrences_of_a_word(self):
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self.assertEqual(
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count_words("one fish two fish red fish blue fish"),
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{"one": 1, "fish": 4, "two": 1, "red": 1, "blue": 1},
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)
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def test_handles_cramped_lists(self):
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self.assertEqual(count_words("one,two,three"), {"one": 1, "two": 1, "three": 1})
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def test_handles_expanded_lists(self):
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self.assertEqual(
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count_words("one,\ntwo,\nthree"), {"one": 1, "two": 1, "three": 1}
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)
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def test_ignore_punctuation(self):
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self.assertEqual(
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count_words("car: carpet as java: javascript!!&@$%^&"),
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{"car": 1, "carpet": 1, "as": 1, "java": 1, "javascript": 1},
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)
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def test_include_numbers(self):
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self.assertEqual(
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count_words("testing, 1, 2 testing"), {"testing": 2, "1": 1, "2": 1}
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)
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def test_normalize_case(self):
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self.assertEqual(count_words("go Go GO Stop stop"), {"go": 3, "stop": 2})
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def test_with_apostrophes(self):
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self.assertEqual(
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count_words("First: don't laugh. Then: don't cry."),
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{"first": 1, "don't": 2, "laugh": 1, "then": 1, "cry": 1},
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)
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def test_with_quotations(self):
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self.assertEqual(
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count_words("Joe can't tell between 'large' and large."),
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{"joe": 1, "can't": 1, "tell": 1, "between": 1, "large": 2, "and": 1},
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)
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def test_substrings_from_the_beginning(self):
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self.assertEqual(
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count_words("Joe can't tell between app, apple and a."),
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{
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"joe": 1,
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"can't": 1,
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"tell": 1,
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"between": 1,
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"app": 1,
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"apple": 1,
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"and": 1,
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"a": 1,
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},
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)
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def test_multiple_spaces_not_detected_as_a_word(self):
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self.assertEqual(
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count_words(" multiple whitespaces"), {"multiple": 1, "whitespaces": 1}
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)
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def test_alternating_word_separators_not_detected_as_a_word(self):
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self.assertEqual(
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count_words(",\n,one,\n ,two \n 'three'"), {"one": 1, "two": 1, "three": 1}
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)
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# Additional tests for this track
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def test_tabs(self):
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self.assertEqual(
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count_words(
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"rah rah ah ah ah roma roma ma ga ga oh la la want your bad romance"
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),
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{
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"rah": 2,
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"ah": 3,
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"roma": 2,
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"ma": 1,
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"ga": 2,
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"oh": 1,
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"la": 2,
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"want": 1,
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"your": 1,
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"bad": 1,
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"romance": 1,
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},
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)
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def test_non_alphanumeric(self):
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self.assertEqual(
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count_words("hey,my_spacebar_is_broken"),
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{"hey": 1, "my": 1, "spacebar": 1, "is": 1, "broken": 1},
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)
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def test_multiple_apostrophes_ignored(self):
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self.assertEqual(count_words("''hey''"), {"hey": 1})
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if __name__ == "__main__":
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unittest.main()
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